Question

the handle of a water pump is 90cm long from its piston Road. if the pivot handle is at a distance of 15 cm from the piston rod, calculate (a) least effort required at its other end to overcome a resistance of 60kgf and (b) mechanical advantage of handle. answer a=12kgf b=5

Answer 1

first we find 
(b) mechanical advantage = (effort arm) / (load arm)
                                     = (90 - 15) / 15
                                     = 5
(a) effort required = load / mechanical advantage = 60 / 5
                             = 12 kgf

i hope it will help you
regards

Answer 2

Mechanical advantage=(effort arm/load arm)

=(90-15)/15

=5

Effort required=load/ mechanical advantage

=60/5

=12 kgf