Question

The handle of nutcracker is 20 cm long and is placed 2 cm from its hinge if a force of 30 KGF is placed on the nut it will crack. Calculate the force which has to be applied at the end of the handle to crack the nut

Answer 1

Answer:

W.K.T

Distance of nut from fulcrum (d) = 2 cm

Distance of effort from fulcrum (D) = 18 cm

Load × Load arm = Effort × Effort arm

Load × 2 cm = 36 kgf × 18 cm

Load = 324 kgf

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