Chemistry, asked by dsrinivasan, 3 months ago

The handress of a
water sample containing
81 mgs of Ca CH(CO3)2
and 120 mgs of MgSO4
per lit is.​

Answers

Answered by waliarishika7
0

Answer:

Explanation:

We can calculate the hardness of given water sample as:

(i) Ca(HCO3​)2​CaCO3≡CaCO3​

162ppm≡100ppm

∴81ppm≡50ppm

(ii) Mg(HCO3​)2​≡CaCO3​

146 ppm ≡ 100 ppm

∴73ppm≡50ppm

(iii) CaSO4​≡CaCO3​

136ppm≡100ppm

∴68ppm≡50ppm

(iv) MgSO4​≡CaCO3​

120ppm≡100ppm

∴60ppm≡50ppm

Total degree of hardness of water =50×4=200ppm

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