The hanger shown in the diagram is balanced. Both cherries weigh the same, both mushrooms
weigh the same, both carrots weigh the same, and all three strawberries weigh the same.
How many grams does the exotic fruit weigh if the total weight of all ten items is 84 grams?
Assume that all parts of the hanger itself (horizontal bars and vertical strings) weigh nothing?
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Answer:
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Answered by
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56grms
Step-by-step explanation:
In the sixth vertical string on the right, we have two cherries.
Since it is balanced, each of the other 3 strings(3rd, 4th and 5th) on the right will weigh two cherries.
Therefore:
Right Hand Side(3rd, 4th,5th and 6th string) = 4 X 2 Cherries=8 Cherries
The fist string carries a weight of 2 Mushrooms
Therefore the second string will also weight Two Mushrooms.
Left Hand Side(1st and 2nd string)=2 X 2 Mushrooms =4 Mushrooms
Therefore:
Right Hand Side=Left Hand Side
8 Cherries=4 Mushrooms
One Cherry is 7 grams
Therefore:
4 Mushrooms =7 X 8 =56 Grams
The total weight of the left hand side is 56 grams. Therefore, the exotic fruit weighs 56 grams.
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