Question

The hardness of water sample containing 10^-3 m caso4

Answer 1

Answer:

The naswer is 100ppm

Explanation:

Given data:

Moles of CaSO4 = 10–3 moles  

Mass of water = 1000g  

DOH (in terms of CaCO3) = (10-3 x 100)/1000 x 106 = 100ppm

Thus the hardness of water in 10–3 moles is 100 parts per million.

Answer 2

Given data :

Moles of CaSO$_{4}$ in water sample = $10^{-3}$ moles  

To find :

The hardness of the water sample .

Solution :

Moles of CaSO$_{4}$ in water sample = $10^{-3}$ moles  

Mass of water ( H$_{2}$O ) = 1000 gram 

Harness of water ( in terms of equivalents of CaCO$_{3}$ )

= ($10^{-3}$  * 100) / 1000 * $10^{6}$  

= 100 ppm

The hardness of the water sample containing $10^{-3}$ moles of CaSO$_{4}$ is 100 parts per million.