Question

The hardness of water sample containing 2 x 10-³g of CaCO3 dissolved in 1 L of water is expressed as a)20 ppm b)2 ppm c) 200 ppm d)0.2 ppm​

Answer 1

2 x 10-³ g of CaCO3 dissolved in 1 L of 3 water is expressed as 2ppm

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Answer 2

Given:

Weight of CaCO3 dissolved in 1L = $2 \times 10^{-3} g$

To Find:

ppm of CaCO3 / Hardness of water sample =?

Explanation:

Now, it is given that 1L = $10^{3} ml$ contains $2 \times 10^{-3} g$ CaCO3

we know that ppm is nothing just parts per million that is in simple words the g of CaCO3 in $10^{6} ml$

therefore if

$10^{3} ml$ contains $2 \times 10^{-3} g$ CaCO3

then,

$10^{6} ml$ contains $2 \times 10^{-3} \times 10^{3} g$ CaCO3 = 2ppm

Therefore, the correct option would be option b or 2 ppm