The harmonic conjugate of (5,1) with respect to the points (2, 10) and (6 , -2) is
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P(5,1) is harmonic conjugate with respect to (2,10) and (6,-2)
the ratio of which P divide AB is
let A(x1,y1) be (2,10)
B(x2,y2) be (6,-2)
P(x,y) be ( 5,1)
Harmanic point divides the line AB in the ratio m : n
m : n = x1-x : x-x2
=2-5: 5-6
3 : 1 let this be m:n m=3 , n=1
therefore harmonic conjugate is {( m(x2)+n(x1))/m+n , (m(y2 )+ n(y1))/m+n}
= { 3(6) +1(2) / 3+1 , 3(-2) +1(10)/3+1 }
=(20/4, 4/4)
=(5,1)
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1
Answer:
5,1
Step-by-step explanation:
Hope I was usefull
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