Math, asked by aniketb6495, 1 year ago

The harmonic conjugate of (5,1) with respect to the points (2, 10) and (6 , -2) is

Answers

Answered by prhareesh2002
17

P(5,1) is harmonic conjugate with respect to (2,10) and (6,-2)

the ratio of which P divide AB is

let A(x1,y1) be (2,10)

    B(x2,y2) be (6,-2)

    P(x,y)    be ( 5,1)

Harmanic point divides the line AB in the ratio m : n

m : n = x1-x : x-x2

        =2-5: 5-6

3 : 1 let  this be m:n      m=3    ,   n=1

therefore harmonic conjugate is {( m(x2)+n(x1))/m+n , (m(y2 )+ n(y1))/m+n}

= { 3(6) +1(2) / 3+1 ,  3(-2) +1(10)/3+1 }

=(20/4, 4/4)

=(5,1)

Answered by adi1423tya
1

Answer:

5,1

Step-by-step explanation:

Hope I was usefull

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