Question

The harmonic mean of A and B is 1/3
and C and D is 1/5 what is the harmonic mean of ABCD​

Answer 1

Answer:

harmonic mean = 15/2

Step-by-step explanation:

• since, 2/(1/A +1/B)=2AB/(A+B)=1/3 ,2/(1/C+1/D)=2CD/(C+D) = 1/5 {GIVEN}. Harmonic mean of ABCD = 2/{(1/A+1/B + 1/C +1/D)}. = 2/ { (AB/A+B) +(CD/C+D)}. =2/{1/6+1/10} =2/{8/30} = 60/8 = 15/2. here , AB/(A+B)= 1/6 , CD/(C+D)=1/10 [ FROM GIVEN DATA]. IF IT WOULD HELP YOU THEN FOLLOW ME!!!!!!!!!

Answer 2

Answer:

Hm A&B = 1/3

Hm C&D = 1/5

then Hm A,B,C,&D = ?

Hm A,B,C,D = A&B + C&D

=1/3 + 1/5

=2/8

=1/4