Math, asked by ja969088, 8 months ago

The HC.F and L.C.M of two numbers are 14 and their L.C.M is 168. If one of the numbers is 56, find the other number?

Answers

Answered by Anonymous
5

Answer:

HCF× LCM= a×b

14×168=56×b

56×b=14×168

56×b=2352

b=2352/56

b=42

other number is 42

Answered by hk9931077412
1

Answer:

42

Step-by-step explanation:

Product of lcm and hcf of two numbers = product of the numbers

Let the other number be X

Therefore,

14*168=56*x

=>2352=56*x

=>X=2352÷56=42

HOPE IT'S HELP

MARK AS BRAINLIEST

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