Question

The HCF and L.C.M of two numbers are 3 and 60 respectively of one of them is 12 find the other.​

Answer 1

Step-by-step explanation:

Given, HCF=12, LCM=72

One number =x, Other number =60−x

∴ Product of the two numbers = HCF × LCM

⇒x(60−x)=12×72

⇒x

2

−60x+864=0

⇒x

2

−36x−24x+864=0

⇒x(x−36)−24(x−36)=0

⇒(x−36)(x−24)=0

⇒x=36 or 24

∴ One of the number is 24.

Answer 2

Answer:

15

Step-by-step explanation:

x * y = HCF * LCM

12 * y = 3 * 60

12 * y = 180

y = 180/12

y = 15

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