Question

the HCF and LCM of 9 and 15 are the sum and product of zeroes of polynomial then find polynomial​

Answer 1

The required polynomial is = x²-3x+45.

(Refer to the above attachment)

Answer 2

Answer:

Question :

The HCF and LCM of 9 and 15 are the sum and product of zeroes of polynomial then find polynomial .

. Solution .

9 = 3 × 3

15 = 3 × 5

So , HCF = 3

&

LCM = 3 × 5 × 3 = 45

[ Sum of zeroes ] HCF = 3

[ Sum of product ] LCM = 45

Formula of polynomial :

K [ x^2 - [ Sum of zeroes ] x + Product )

= K [ x^2 - 3x + 45 ]

Polynomial = K [ x^2 - 3x + 45 ] .