Question

the hcf and lcm of two digit numbers are 16 and480 which are the numbers?

Answer 1

Let two numbers are x and y.

Given : HCF is 16 and LCM is 480.

Now , x=16 a and y =16 b ; where a and b are relative prime numbers of each others.

Now, 16ab =LCM of x and y

16ab = 480

ab = 480/16 = 30

Now, relative prime to each other are (2,15), (3,10), (5,6).

Thus, numbers may be (32,240), (48,160), (80,96) .

Hence, required two digit numbers are 80 and 96 .