Question

the hcf and lcm of two no. are 18 and 720 if one of the no. exceeds other by 54 find both no.

Answer 1

Answer:

a=144,b=90

Step-by-step explanation:

hcf*lcm=a*b

18*720=a*b

12960=a*b

a-b=54

a=b+54

12960=(b+54)(b)

12960=b²+54b

b²+54b-12960=0

for a quadratic equation ax²+bx+c

x = [-b±√(b² - 4ac)]/2a.

here a=1,b=54,c=-12960

b=-54+√(2916+51840)/2

b={-54+√54756}/2

b={-54+234}/2

b=180/2

b=90

a-b=54

a-90=54

a=90+54

a=144

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