the hcf and lcm of two no. are 18 and 720 if one of the no. exceeds other by 54 find both no.
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Answer:
a=144,b=90
Step-by-step explanation:
hcf*lcm=a*b
18*720=a*b
12960=a*b
a-b=54
a=b+54
12960=(b+54)(b)
12960=b²+54b
b²+54b-12960=0
for a quadratic equation ax²+bx+c
x = [-b±√(b² - 4ac)]/2a.
here a=1,b=54,c=-12960
b=-54+√(2916+51840)/2
b={-54+√54756}/2
b={-54+234}/2
b=180/2
b=90
a-b=54
a-90=54
a=90+54
a=144
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