Question

The HCF and LCM of two no. are 7 and 252 respectively .If one no. is 28 and find the other no.

Answer 1

HCF × LCM = Product of 2 no

• Number 1: 28
• Number 2: x
• H.C.F = 7
• L.C.M = 252

→ 7 × 252 = 28 × x

→ 7 × 252 = 28x

→ 7 × 252 × 1/28 = x

→ 7 × 9 = x

→ 63 = x

Hence the other number none other than 63.

_________________________

Verification

→ 63 × 28 = 252 × 7

→ 1764 = 1764

→ L.H.S = R.H.S

Q.E.D

Answer 2

$\mathbf{\huge{\underline{\boxed{63}}}}$

Given:

HCF = 7

LCM = 252

ONE NUMBER = 28

____________________________

To find:

Other number

____________________________

Solution:

We have formula:-

$\mathbb{\huge{\underline{\boxed{L.C.M * H.C.F = PRODUCT OF NUMBERS}}}}$

_________[Put values]

7 × 252 = 28 × Other number

Other number = 63

$\rule{200}{1}$

So, other number is 63