Question

the HCF and LCM of two number are 29 and 1160 respectively .if one of the number is 145 .find the other​

Answer 1

ANSWER:-

Given:

The H.C.F. & L.C.M. of two number are 29 & 1160 respectively. If one of the number is 145.

To find:

Find the other number.

Solution:

Let the other number be x.

We know that,

H.C.F. × L.C.M.= product of two number.

therefore,

=) 29 × 1160 = 145 × x

$x = \frac{29 \times 1160}{145} \\ \\ = > x = 29 \times 8 \\ \\ = > x = 232$

The other number is 232.

Hope it helps ☺️

Answer 2

Step-by-step explanation:

The H.C.F. & L.C.M. of two number are 29 & 1160 respectively. If one of the number is 145.

To find:

Find the other number.

Solution:

Let the other number be x.

We know that,

H.C.F. × L.C.M.= product of two number.

therefore,

=) 29 × 1160 = 145 × x

\begin{lgathered}x = \frac{29 \times 1160}{145} \\ \\ = > x = 29 \times 8 \\ \\ = > x = 232\end{lgathered}

x=

145

29×1160

=>x=29×8

=>x=232

The other number is 232.

Hope it helps ☺️