Question

the HCF and LCM of two numbers are 12 and 5040 , respectively . if one of the numbers is 144 , find the other number?​

Answer 1

Solve this question by using below formula.

Product of 2 numbers = product of their HCF and LCM

144 * x = 12 * 5040

x = (12*5040)/144 = 420

Answer 2

$\Large\bold{\mathcal{\colorbox{yellow}{\blue{Solution:⤵}}}} \\ \large \bold{ \mathtt{ \colorbox{red}{ \blue{Given \: HCF=12,LCM=5040}}}} \\ \large \bold{ \mathcal{ \colorbox{pink}{ \pink{and also one number is 144}}}} \\ \large \bold{ \mathtt{ \colorbox{yellow}{ \blue{Let the other number be x}}}} \\ \large \bold { \mathtt{ \colorbox{orange}{{As we know that}}}} \\ \large \bold{ \mathtt{ \colorbox{navy}{ \orange{Product of two numbers is HCF×LCM}}}} \\ \large \bold{ \mathtt{ \colorbox{orange}{ \red{⟹144×x=12×5040}}}} \\ \large \bold{ \mathtt{ \colorbox{lime}{ \purple{⟹x=420}}}} \\ \large \bold{ \mathtt{ \colorbox{aqua}{ \red{So, The other number is 420}}}}$

Answer 3

$\Large\bold{\mathcal{\colorbox{yellow}{\blue{Solution:⤵}}}} \\ \large \bold{ \mathtt{ \colorbox{red}{ \blue{Given \: HCF=12,LCM=5040}}}} \\ \large \bold{ \mathcal{ \colorbox{pink}{ \pink{and also one number is 144}}}} \\ \large \bold{ \mathtt{ \colorbox{yellow}{ \blue{Let the other number be x}}}} \\ \large \bold { \mathtt{ \colorbox{orange}{{As we know that}}}} \\ \large \bold{ \mathtt{ \colorbox{navy}{ \orange{Product of two numbers is HCF×LCM}}}} \\ \large \bold{ \mathtt{ \colorbox{orange}{ \red{⟹144×x=12×5040}}}} \\ \large \bold{ \mathtt{ \colorbox{lime}{ \purple{⟹x=420}}}} \\ \large \bold{ \mathtt{ \colorbox{aqua}{ \red{So, The other number is 420}}}}$

Answer 4

$\Large\bold{\mathcal{\colorbox{yellow}{\blue{Solution:⤵}}}} \\ \large \bold{ \mathtt{ \colorbox{red}{ \blue{Given \: HCF=12,LCM=5040}}}} \\ \large \bold{ \mathcal{ \colorbox{pink}{ \pink{and also one number is 144}}}} \\ \large \bold{ \mathtt{ \colorbox{yellow}{ \blue{Let the other number be x}}}} \\ \large \bold { \mathtt{ \colorbox{orange}{{As we know that}}}} \\ \large \bold{ \mathtt{ \colorbox{navy}{ \orange{Product of two numbers is HCF×LCM}}}} \\ \large \bold{ \mathtt{ \colorbox{orange}{ \red{⟹144×x=12×5040}}}} \\ \large \bold{ \mathtt{ \colorbox{lime}{ \purple{⟹x=420}}}} \\ \large \bold{ \mathtt{ \colorbox{aqua}{ \red{So, The other number is 420}}}}$

Answer 5

$\Large\bold{\mathcal{\colorbox{yellow}{\blue{Solution:⤵}}}} \\ \large \bold{ \mathtt{ \colorbox{red}{ \blue{Given \: HCF=12,LCM=5040}}}} \\ \large \bold{ \mathcal{ \colorbox{pink}{ \pink{and also one number is 144}}}} \\ \large \bold{ \mathtt{ \colorbox{yellow}{ \blue{Let the other number be x}}}} \\ \large \bold { \mathtt{ \colorbox{orange}{{As we know that}}}} \\ \large \bold{ \mathtt{ \colorbox{navy}{ \orange{Product of two numbers is HCF×LCM}}}} \\ \large \bold{ \mathtt{ \colorbox{orange}{ \red{⟹144×x=12×5040}}}} \\ \large \bold{ \mathtt{ \colorbox{lime}{ \purple{⟹x=420}}}} \\ \large \bold{ \mathtt{ \colorbox{aqua}{ \red{So, The other number is 420}}}}$