Question

the HCF and LCM of two numbers are 12 and 5040 , respectively . if one of the numbers is 144 , find the other number?​

Answer 1

$\begin{gathered}\frak{Given}\begin{cases}& \sf{HCF\;of\;two\; Numbers =\frak{12}} \\ &\sf{LCM\;of\;two\;numbers=\frak{5040}} \\ &\sf{One\;of \: the \: number\;is=\frak{144}}\end{cases}\end{gathered}$

Need to find: The other number?

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❍ Let the other required number be x respectively.

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$\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}$

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$\bf{\star}\;\boxed{\textsf{\textbf{\pink{Product\;of\;two\; Numbers\;=\;LCM \times \: HCF}}}}⋆$

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Therefore,

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$\begin{gathered}:\implies\sf x \times 144 = 12 \times 5040\\\\\\:\implies\sf x \times 144 = 60480 \\\\\\:\implies\sf x = \cancel\dfrac{60480}{144} \\\\\\:\implies{\underline{\boxed{\pink{\frak{x = 420}}}}}\;\bigstar\end{gathered}$

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$\therefore{\underline{\textsf{Hence, the other required number is {\textbf{420.}}}}}$

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$\begin{gathered}\qquad\quad\boxed{\underline{\underline{\pink{\bigstar \: \bf\:More\:to\:know\:\bigstar}}}}\\ \\\end{gathered}$

HCF is (Highest common factor) which is the greatest factor b/w given any numbers.

LCM is (Lowest common factor) which is the least number and LCM is exactly divisible by two or more numbers.

Answer 2

$\bold{ \pmb{GIVEN}} \\ \red{ \tt HCF \: of \: two \: numbers} = 12 \\ \tt \red{ \: LCM \: of \: two \: number} = 5040 \\ \tt \red{ \: One \: number }= 144 \\ \\ \\ \bold{\pmb{TO \: \: FINd}} \\ \bf{ \: Other \: number} \\ \\ \\ \bold{ \pmb{SOLUTION}} \\ \\ \small{\boxed{\cal{LCM \times HCF = Product \: of \: two \: numbers}}} \\ \\ \sf \: Let \: the \: other \: number \: be \: b \\ \rm 12 \times 5040 = 144 \times b \\ \rm 60480 = 144b \\ \rm \: b = \dfrac{60480}{144} \\ \\ \boxed{\bold {\pmb{\blue{\underline{ \dag \: \: Other \: \: number = 420}}}}}$