The hcf and lcm of two numbers are 12 and 72 respectively.if the sum of the two numbers is 60,what is the smallest of two numbers?
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let the two numbers be x and y. their common factor is 12, and x+y=60, the smallest number that is multiple of both numbers is 72. now hcf*LCM=xy
12*72=xy=864 , now x=864/y and solving them u can get that y is smaller than x
12*72=xy=864 , now x=864/y and solving them u can get that y is smaller than x
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