Question

The hcf and lcm of two numbers are 12 and 72 respectively.if the sum of the two numbers is 60,what is the smallest of two numbers?

Answer 1

let the two numbers be x and y. their common factor is 12, and x+y=60, the smallest number that is multiple of both numbers is 72. now hcf*LCM=xy
12*72=xy=864 , now x=864/y and solving them u can get that y is smaller than x