The HCF and LCM of two numbers are 17 and 3570. How many such pair exist?
Answers
Answered by
0
Answer:
Let the numbers be 16a and 16b, where a and b are co-primes.
We know that LCM×HCF=Product of two numbers, therefore, we have,
16a×16b=(16×146)
⇒256ab=16×146
⇒ab=
256
16×146
⇒ab=9.125
The co-primes with product 9.125 does not exist.
Hence, the number of possible pairs are zero.
Answered by
0
Answer
Let the numbers be 16a and 16b, where a and b are co-primes.
We know that LCM×HCF=Product of two numbers, therefore, we have,
16a×16b=(16×146)
⇒256ab=16×146
⇒ab=
256
16×146
⇒ab=9.125
The co-primes with product 9.125 does not exist.
Hence, the number of possible pairs are zero.
Similar questions