Question

The HCF and LCM of two numbers are 23 and 1449. If one of the numbers is

161, find the other.​

Answer 1

Answer:

(a×b) = ( HCF (a ,b) × ( LCM (a,b)) . Here a '= 161 , HCF = w23 and LCM = 1449. And we have to find b. Hence , the other number is 207.

Step-by-step explanation:

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Answer 2

Answer:

The other number is 207

Step-by-step explanation:

Let the unknown number be = x

Now we know that

Product of two numbers = Product of their HCF & LCM

Therefore according to the above relation here we get

$\implies x*161 = 23*1449 = 33327\\\\\implies x=\frac{33327}{161} \\\\\implies x = 207$

Therefore the other number  = 207