the HCF and Lcm of two numbers are 4 and 8 respectively one of the numbers is16 find the other
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let the two no's be a and a
LCM(a,b) × HCF (a,b)= ab
4×8= 16 a
32= 16a
therefore a =2
Hence the other no. is 2
LCM(a,b) × HCF (a,b)= ab
4×8= 16 a
32= 16a
therefore a =2
Hence the other no. is 2
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