Question

The HCF and LCM of two numbers are 48 and 288 respectively.One of the numbers is 144. Find the other number.​

Answer 1

Answer:

HCF = 48

LCM = 288

First number = 144

Second number = ?

Since, HCF X LCM = Product of the two numbers

Therefore, 48 X 288 = 144 X second number

= 48 X 2

= 96

Thus, the other number is 96.

Answer 2

Answer:

hi dear

Step-by-step explanation:

your answer is 96

One number is 144.

One number is 144.Let another number be x.

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, then

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)144\times x=288\times 48144×x=288×48

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)144\times x=288\times 48144×x=288×48144\times x=13824144×x=13824

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)144\times x=288\times 48144×x=288×48144\times x=13824144×x=13824x=\frac{13824}{144}x=

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)144\times x=288\times 48144×x=288×48144\times x=13824144×x=13824x=\frac{13824}{144}x= 144

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)144\times x=288\times 48144×x=288×48144\times x=13824144×x=13824x=\frac{13824}{144}x= 14413824

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)144\times x=288\times 48144×x=288×48144\times x=13824144×x=13824x=\frac{13824}{144}x= 14413824

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)144\times x=288\times 48144×x=288×48144\times x=13824144×x=13824x=\frac{13824}{144}x= 14413824

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)144\times x=288\times 48144×x=288×48144\times x=13824144×x=13824x=\frac{13824}{144}x= 14413824 x=96x=96

One number is 144.Let another number be x.It is given that HCF and LCM of two numbers are 48 and 288 respectively.If a and b are two numbers, thena\times b=LCM(a,b)\times HCF(a,b)a×b=LCM(a,b)×HCF(a,b)144\times x=288\times 48144×x=288×48144\times x=13824144×x=13824x=\frac{13824}{144}x= 14413824 x=96x=96Therefore the another number is 96.