Question

The HCF and LCM of two numbers are 5 and 46,905 respectively. If one of the numbers is 265, find the other.​

Answer 1

Answer:

Let one number =x Then other number =100−x

LCM =495 and HCF=5

Product of number =HCF×LCM

∴x(100−x)=495×5

⇒100x−x

2

=2475

⇒x

2

−100x+2475=0

⇒x

2

−45x−55x+2475=0

⇒x(x−45)−55(x−45)=0

⇒(x−45)(x−55)=0

⇒x=45 or 55

∴ The one numbers is 45, then another number =100−45=55 or

if one number is 55, then another number =100−55=45

∴ Required difference =55−45=10