The HCF and LCM of two numbers are 6 and 30 respectively. If one of the numbers is 60 then find the other number
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2
Answer:
Sol) HCF = 6
LCM = 30
One of the number = 60
Other number = HCF×LCM/One of the number
= 6 × 30 / 60
= 3
So the other number is 3.
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Answered by
0
Answer:
30
Step-by-step explanation:
If a, b are two numbers and their HCF = H , LCM = L then
Here, a =60 and b=?
Hcf/H=6 and Lcm/L=30
We know,
a×b=H×L
≈60×b=6×30
≈b=6×30/60
≈b=3
Hence the required number is 30
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