the hcf and lcm of two numbers are 6 and 60 respectively if one of the number is 12 find the other numbers
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1
Answer:
i) HCF of 10 and 36=2
(ii) HCF of 24 and 15=3
(iii) HCF of 12 and 30=6
(iv) HCF of 18 and 20=2.
Hence Correct option choice is (C).
So, LCM × HCF =60×6=360
First number × second number =12×30=36
Product of 2 numbers = LCM*HCF
Let the other number be "a"
=> a*12 = 6*60
=> a = 360/12
=> a = 30
Therefore the other number is 30
Answered by
0
Answer:
30
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