Question

The HCF and LCM of two numbers are 6 and 864 respectively. If one number is 96, then find the other number. ​

Answer 1

Given that:- HCF $=6$ and LCM$=864$

First number $=96$

To find:- The second number

Let, the second number be x

As the product of HCF and LCM is equal to the product of two numbers.

$=>6\times 864=96\times x$

$=>5184=96x$

$=>x=\frac{5184}{96}$

$=>x=54$

Hence, the other number is 54.

Answer 2

• As per the data given in the question, we have to find the required number.

       Given data- Hcf=$6$.  

                    Lcm=$864$.

       The First number is $96$ .

       To find:- the second number.

       Solution:-

       Here, we are using the relation of $Hcf$ and $\mathrm{Lcm}$ of two numbers.

       Therefore,

$\begin{array}{l}\Rightarrow \text { Product of two numbers }=\text { Product of hcf and lcm.} \te \\\Rightarrow 96 \times \text { secondnumbers }=6 \times 864 . \\\Rightarrow 96\times second number=6 \times 864 \\\Rightarrow x=\frac{6 \times 864}{96} \\\Rightarrow x=54.\end{array}$

Hence, the second number will be $84.$ .