Math, asked by javedakhtar53, 8 months ago

THE HCF AND LCM OF TWO NUMBERS ARE 8 AND
168 RESPECTIVELY. IF ONE OF THE NUMBER IS 56
FIND THE OTHER

Answers

Answered by XxJAHANGIRxX
0

Step-by-step explanation:

The HCF of two numbers is 4 and their LCM = 168.

If one number is 12 the other number = (4*168)/12 = 56.

Check:

12 = 2x2x3

168 = 2x2x2x3x7

HCF = 2x2 = 4 and LCM = 2x2x2x3x7 = 168. Correct

The other number is 56.

Answered by sonal6199
1

Step-by-step explanation:

hcf of the no =8

LCM of the no =168

one of the no is equal to 56

let another number be=y

we know that

LCM × HCF = product of the numbers

8×168=56×y

1344=56×y

y=1344/56

=24

therefore another number is 24

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