Question

The HCF and LCM of two numbers are
8 and 1728, respectively. Accordingly,
how many pairs of such digits are there?​

Answer 1

Answer:

X and Y can't both have 3 as a factor - if they did, then the HCF would be 24, not 8. But there must be a 3^3 somewhere, otherwise the LCM wouldn't be 1728. Therefore one of b and d is 0, and the other is 3.

Step-by-step explanation:

Answer 2

simplify karne ka tarika sir BODMAS hai easy and simple