Math, asked by brianilistJahan, 4 months ago

The HCF and LCM of two numbers are 8 and 1728, respectively. Accordingly, how many pairs of such digits are there?​

Answers

Answered by yashrajmakariye
3

Answer:

X and Y can't both have 3 as a factor - if they did, then the HCF would be 24, not 8. But there must be a 3^3 somewhere, otherwise the LCM wouldn't be 1728. Therefore one of b and d is 0, and the other is 3.

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