Question

the HCF AND LCM of two numbers are 9 and 360 respectively if one of the numer is 45 write another number

Answer 1

The other number is 72

Given:

H .C .F of two numbers are 9 and 360

To Find:

The other number

Solution:

By formula

$\mathrm{H} \cdot \mathrm{C} . \mathrm{F} \times \mathrm{L} . \mathrm{C} . \mathrm{M}$ of two numbers = product of the two numbers

$\mathrm{H} \cdot \mathrm{C} \cdot \mathrm{F} \times \mathrm{L} \cdot \mathrm{C} \cdot \mathrm{M}=9 \times 360$

Given in question, one of the numbers is 45

Let the another number be x

Therefore, substituting the terms in the above formula,  

$\begin{array}{l}{9 \times 360=45 \times x} \\ {x=\frac{9 \times 360}{45}} \\ {x=72}\end{array}$

Answer 2

Answer:

$Second \: number = 72$

Step-by-step explanation:

/* We know that,

If a, b are numbers their HCF = h and LCM = l then

a × b = h × l */

Here,

a = 45, b = ?

h = 9 , l = 360

$45 \times b = 9 \times 360$

$\implies b = \frac{9\times 360}{45}$

$\implies b = 72$

Therefore,

$Second \: number = 72$

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