The HCF and LCM of two numbers is 4 and 288 respectively.Find the two numbers.
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4x+4y = 288
x + y = 288/4
x + y = 72
xy = 4 *288
(72-y)(y) = 1152
72y-y^2 = 1152
=y^2-72y+1152
=(y-48) (y-24)
Y= 48,24
X= 24,48
x + y = 288/4
x + y = 72
xy = 4 *288
(72-y)(y) = 1152
72y-y^2 = 1152
=y^2-72y+1152
=(y-48) (y-24)
Y= 48,24
X= 24,48
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