The HCF and LCM of two numbers is 5 and 30 respectively. If one of the numbers is 10, find the other number. Do it by the method
Answers
Answer:
15
Step-by-step explanation:
Given, LCM=5, HCF=30 and one number is 10. =15. other number=15
\large\underline{\sf{\blue{Correct \: Question:}}}
CorrectQuestion:
The HCF and LCM of two numbers is 5 and 30 respectively. If one of the number is 10, find the other number
\large\underline{\sf{\blue{Given:}}}
Given:
We have been that HCF and LCM of two numbers is 5 and 30 respectively
One number is 10
\large\underline{\sf{\blue{To \: Find :}}}
ToFind:
We have to find the other number
\large\underline{\sf{\blue{Solution:}}}
Solution:
Let the other number be = x
HCF of numbers = 5
LCM of numbers = 30
\large\underline{\mathfrak\red{We \: know \: that :}}
Weknowthat:
\mapsto \boxed{\sf{HCF \times LCM = Product \: of \: Numbers}}↦
HCF×LCM=ProductofNumbers
\mapsto \sf{5 \times 30 = x \times 10}↦5×30=x×10
\mapsto \sf{10x = 150}↦10x=150
\mapsto \sf{x = \dfrac{150}{10}}↦x=
10
150
\mapsto \boxed{\sf{x = 15}}↦
x=15
\sf{}
Hence the other Number is 15