The hcf and lcm of two numvbers are 12 and 72 respectively. if the sum of thesenumber is 60 then one of the number will be
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Given:
Let the two numbers be x & y
x+y = 60..............(1)
H.C.F= 12, L.C.M= 72
H.C.F × L.C.M = PRODUCT OF 2 NUMBERS
12 × 72 = XY
864 = XY
X= 864/y..............(2)
Put this value of x in eq 1
x+y= 60
864/y + y= 60
(864+ y²)/y = 60
864 + y² = 60 y
y² -60y +864=0
y² -36y -24y+864=0
y(y-36)-24(y-36)=0
(y-36)(y-24)= 0
y-36= 0
y=36
y-24=0
y=24
Put the value of y= 36
x+y=60
x+ 36= 60
x= 60 -36= 24
x= 24
If y= 36, then x= 24
If y=24, then x= 36
Hence, the numbers are 36 & 2
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