Question

the HCF and LCM of two polynomial P(x) and Q(x) are X(x+p) and 12x²(x-p) (x²-p²) respectively. If p(X) = 4x²(X+p) , then Q (X) =​

Answer 1

Answer:

Explanation:

HCF = x(x+p)

LCM= 12 x^2 (x-p) (x^2 - p^2)

p(x) = 4x^2(x+p), q(x) = ?

p(x) x q(x) = HCF x LCM

q(x) = [x (x+p) x 12 x^2 (x-p) (x^2 - p^2)] / 4 x^2(x+p)  

      = [ x^3  (x+p)^2 (12) (x-p)^2 ] / 4 x^2 (x+p)

      =  3 x (x+p) (x-p)^2

Answer 2

Answer:

3x(x-p)(x^2-p^2)

Explanation:

x(x+p)×12x^2(x-p)(x^2-p^2)=q(x)×4x^2(x+p)

q(x)=x(x+p)×12x^2(x-p)(x^2-p^2)÷4x^2(x+p)

q(x)=3x(x-p)(x^2-p^2) ans