The HCF and LCM of two polynomials P(x) and
Q(x) are (2x-1) and (6x³ + 25x² - 24x + 5)
respectively. If P(x) = 2x²+9x – 5, determine
Q(x)
(a) 6x²- 5x+1 (b) 6x² + 5x +1
(c) 6x² - 5x-1 (d) 6x²+ 5x-1
Answers
Answered by
8
Answer:
6x^2-5x+1=Q(x)
Step-by-step explanation:
because
Lcm×hcf=ab
lcm×hcf/a=b
Answered by
0
Answer:
option (a)
Step-by-step explanation:
HCF * LCM = a*b
HCF * LCM = P(x) * Q(x)
Q(x) = HCF * LCM / P(x)
Q(x) = (2x - 1) * (6x^3+25x^2-24x+5) ÷ (2x^2+9x-5 )
= 12x^4+50x^3-48x^2+10x-6x^3-25x^2+24x-5 /
2x^2 +9x-5
= 12x^4 +44x^3-73x^2+34x-5 / 2x^2+9x-5
After solving by long division method ;
Dividend = 12x^4 +44x^3-73x^2+34x-5
Divisor = 2x^2+9x-5
Remainder = 0
Quotient = 6x^2-5x+1
Therefore ; Q(x) = 6x^2-5x+1
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