The HCF and the LCM of 12, 21, 15 are recpectively
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2
Answer:
we take all the factors present in three numbers and the highest power of the common factors respectively. Therefore, the required H.C.F. and L.C.M. of 12, 21 and 15 are 3, 420 respectively.
Answered by
1
Answer:
HCF
12 =1,2, 3,4,6,12
21= 1,3,7,21
15= 1,3,5,15
common in all = 3
HCF = 3
LCM
3×4× 7×5
84 × 5
420
LCM = 420
The HCF and the LCM of 12, 21, 15 are recpectively 3 and 420
hope it is helpful
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