The HCF and the LCM of two digits no. Are 2 and 644 respectively. Find the numbers
Answer is 28 and 46
but how??
Answers
Answered by
10
Let the numbers be 2x and 3x
LCM of 2x and 3x = 6x (∵ LCM of 2 and 3 is 6. Hence LCM
of 2x and 3x is 6x)
Given that LCM of 2x and 3x is 48
=> 6x = 48
=> x = 48⁄6 = 8
Sum of the numbers = 2x + 3x = 5x = 5 × 8 = 40
LCM of 2x and 3x = 6x (∵ LCM of 2 and 3 is 6. Hence LCM
of 2x and 3x is 6x)
Given that LCM of 2x and 3x is 48
=> 6x = 48
=> x = 48⁄6 = 8
Sum of the numbers = 2x + 3x = 5x = 5 × 8 = 40
Answered by
2
Answer:
The correct answer will be -
28, 46
14, 92
Step-by-step explanation:
Given in the question
HCF of the given two numbers is = 2
LCM of the two numbers is = 644
Now,
Let the numbers be x and y.
If we factorize 644 we will get
644 =
A given the HCF is 2.
The numbers formed will have at least 2 as their factors. Also, only one number will have both 2 as factors because HCF is 2.
Writing such number one combination will be,
x = = 28
y = = 46
Another combination can be -
x = = 92
y = = 14
So two possible pairs are (28, 46) and (14, 92)
#SPJ2
Similar questions