Math, asked by Ayan8235, 1 year ago

The hcf (gcd) of a, b is 12, a, b are positive integers and a > b > 12. The smallest values of (a,
b.Are respectively

Answers

Answered by shameemamk
7

Answer:

a=36 and b=24

Attachments:
Answered by lovingheart
1

Answer:

Smallest value of a & b are (36, 24)

Step-by-step explanation:

Step 1:

Hcf(a,b)=12

Therefore a=12m and b=12n, where m and n are co-prime

Step 2:

a>b>12=12n>2=n>1

Let n=2 then b=12X2=24

Step 3:

Since a>b, and m and n are co-prime smallest value m can have is 3

Therefore a=12x3=36

So the smallest value of a=36 and b=24

Step 4:

HCF (GCD) of a, b number is 12

and a > b > 12 (given)

Step 5:

∴ Smallest value of a & b are (36, 24)

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