The hcf (gcd) of a, b is 12, a, b are positive integers and a > b > 12. The smallest values of (a,
b.Are respectively
Answers
Answered by
7
Answer:
a=36 and b=24
Attachments:
Answered by
1
Answer:
Smallest value of a & b are (36, 24)
Step-by-step explanation:
Step 1:
Hcf(a,b)=12
Therefore a=12m and b=12n, where m and n are co-prime
Step 2:
a>b>12=12n>2=n>1
Let n=2 then b=12X2=24
Step 3:
Since a>b, and m and n are co-prime smallest value m can have is 3
Therefore a=12x3=36
So the smallest value of a=36 and b=24
Step 4:
HCF (GCD) of a, b number is 12
and a > b > 12 (given)
Step 5:
∴ Smallest value of a & b are (36, 24)
Similar questions