Question

The hcf of 1250,9375,15625

Answer 1

Answer:

So, required number = HCF of 1250, 9375 and 15625.

15625 = 9375 x 1 + 6250

9375 = 6250 x 1 + 3125

6250 = 3125 x 2 + 0

=> HCF (15625, 9375) = 3125

3125 = 1250 x 2 + 625

1250 = 625 x 2 + 0

HCF(3125, 1250) = 625

So, HCF (1250, 9375, 15625) = 625

Hence, the largest number is 625.

Answer 2

Answer:

The HCF of the given numbers is 625.

Step-by-step explanation:

Given: The numbers are 1250, 9375, and 15625.

We have to find the HCF of the above numbers.

• As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

The numbers are 1250, 9375, and 15625.

First, we will find the factors of the above numbers.

The factors of 1250 are: $1, 2, 5, 10, 25, 50, 125, 250, 625, 1250$

The factors of 9375 are: $1, 3, 5, 15, 25, 75, 125, 375, 625, 1875, 3125, 9375$

The factors of 15625 are: $1, 5, 25, 125, 625, 3125, 15625$

From the above, we can see that 625 is the largest positive integer that divides each of the integers.

Then the greatest common factor(HCF) is 625.

In this problem, we are assuming we have to find the HCF of the given numbers.

Q. Find HCF of 1250, 9375, and 15625.