Question

:. The HCF of 128 and 68 is expressible in
the form 128 m - 15 X 68. Find the value of
m. Also find the LCM of 128 and 68 using
prime factorisation method.​

Answer 1

Step-by-step explanation:

HCF of 128 and 68

by using division algorithm

128>68

128=68×1+60

68=60×1+8

60=8×7+4

8=4×2+0

therefore HCF of 128 and 68 is 4

4=60-8×7

=>60-(68-60×1)×7

60-68×7+60x7

60+60x7-68x7

60x8-68x7

(128-68x1)x8-68x7

128x8+68x8+68x7

128x8-68x15

therefore m=8