Math, asked by devansh99090, 1 month ago

The HCF of 14pq and 28 p²q² is ______

Answers

Answered by kasturi4887

0

Answer:

the answer is below

Step-by-step explanation:

14pq=14*p*q

28p^2q^2=14*2*p*p*q*q

the highest common factor will be 14pq

hope you understood it

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