Math, asked by vishalsingh4, 1 year ago

The HCF of 1848,3058 and 1331 is:

Answers

Answered by siddhartharao77
58
1848 = 11*2*2*2*3*7

3058 = 11*2*139

1331 = 11*11*11


HCF of 
1848,3058 and 1331 = 11.
Answered by gayatrikumari99sl
0

Answer:

11 is the required HCF of 1848 , 3058 and 1331 .

Step-by-step explanation:

Explanation:

Given  , numbers are  1848 , 3058 and 1331

HCF - The largest positive integer that divides each of the numbers is the greatest common divisor of two or more integers that are not all zero.

Step 1:

factor of 1848 =  2× 2× 2× 3× 7× 11

factor of 3058 =  2 × 11 × 139

factor of 1331 =  11 × 11 × 11

Here , we can see that  11 is the common factor of 1848 , 3058 and 1331 .

Final answer:

Hence , HCF of 1848, 3058 and 1331 is 11 .

#SPJ3

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