The HCF of 1848,3058 and 1331 is:
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Answered by
58
1848 = 11*2*2*2*3*7
3058 = 11*2*139
1331 = 11*11*11
HCF of 1848,3058 and 1331 = 11.
3058 = 11*2*139
1331 = 11*11*11
HCF of 1848,3058 and 1331 = 11.
Answered by
0
Answer:
11 is the required HCF of 1848 , 3058 and 1331 .
Step-by-step explanation:
Explanation:
Given , numbers are 1848 , 3058 and 1331
HCF - The largest positive integer that divides each of the numbers is the greatest common divisor of two or more integers that are not all zero.
Step 1:
factor of 1848 = 2× 2× 2× 3× 7× 11
factor of 3058 = 2 × 11 × 139
factor of 1331 = 11 × 11 × 11
Here , we can see that 11 is the common factor of 1848 , 3058 and 1331 .
Final answer:
Hence , HCF of 1848, 3058 and 1331 is 11 .
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