Question

The HCF of 2^3×3^2×5^4×7×11.2^2×3^3×7^2×11 and2^4×5^2×11 is
​

Answer 1

The HCF of 2^3×3^2×5^4×7×11.2^2×3^3×7^2×11 and2^4×5^2×11 is

Ans:

860

Hope you like it

Plz make me as Brantley

Answer 2

HCF is 44.

$\bf \: HCF ( {2}^{3} \times {3}^{2} \times {5}^{4} \times 7 \times 11, \: {2}^{2} \times {3}^{3} \times {7}^{2} \times 11, \:\: {2}^{4} \times {5}^{2} \times 11) = 44$

Given:

• ${2}^{3} \times {3}^{2} \times {5}^{4} \times 7 \times 11, \: {2}^{2} \times {3}^{3} \times {7}^{2} \times 11, \: and \: {2}^{4} \times {5}^{2} \times 11$

To find:

• Find the HCF.

Solution:

Concept to be used:

We know that HCF of numbers can be find by taking all the common factors in every number.

Step 1:

On analysing the numbers it is clear that

2² is common in all.

11 is common in all.

rest of the factors are not common in all three numbers.

Step 2:

Find HCF.

Thus,

HCF of given numbers is : 2²×11

HCF of given numbers is : 4×11= 44.

Thus,

$HCF ( {2}^{3} \times {3}^{2} \times {5}^{4} \times 7 \times 11, \: {2}^{2} \times {3}^{3} \times {7}^{2} \times 11, \:\: {2}^{4} \times {5}^{2} \times 11) = 44$

Learn more:

1) Hcf of 32 and 144 by prime factorization

https://brainly.in/question/12188837

2) Finthe Hcf and lcm of a and b for the numbers a=2⁵×3⁷×5²×7 and b= 2³×3²×5⁶×11 . Also check if hcf (a,b) × lcm (a,b) = a×...

https://brainly.in/question/20835167