Question

The HCF of 2/5, 6/25 and 8/35 is-
(a) 5/48
(b) 5/8
(c) 75/48
(d) 75/8

Explain Your Answer
❎❌✖Spammers Not Allowed✖❌❎​

Answer 1

Correct question is "

The HCF of 2/5, 6/25 and 8/35 is-

(a) 5/48

(b) 5/8

(c) 75/48

(d) 75/8

(e)None of this "

Answer:

Required HCF is $\frac{2}{175}$

So, option e is the correct answer.

Step-by-step explanation:

Given fractions are

$\frac{2}{5}, \frac{6}{25}, \frac{8}{35}$

We want to find HCF of these fractions.

We know,

HCF of fractions $= \frac{HCF\: of \: numerator}{LCM \: of \: denominator}$

So HCF of

$\frac{2}{5}, \frac{6}{25}, \frac{8}{35}$

$= \frac{HCF \: of \: 2,6,8}{LCM \: of \: 5,25,35}$

HCM means Highest Common Factor.

By prime factorisation,

$2 = 2 \times 1 \\ 6 = 2 \times 3 \\ 8 = 2 \times 2 \times 2$

So,HCF of 2,6,8 is 2.

LCM means Lowest Common Multiples.

By prime factorisation,

$5 = 5 \times 1 \\ 25 = 5 \times 5 \\ 35 = 5 \times 7$

So,LCM of 5,25,35 is (5×5×7) = 175

Therefore HCF of $\frac{2}{5}, \frac{6}{25} , \frac{8}{35}$ is $\frac{2}{175}$

Know more about HCF,

https://brainly.in/question/25945206

https://brainly.in/question/20353612

#SPJ2