Question

the HCF of 2 numbers is 23 and their LCM is 1449.if one of the number is 161 find the another number

Answer 1

Answer:

Let the two numbers be a and b.

Let the value of a be 161.

Given: HCF = 23 and LCM = 1449

We know,

a × b = HCF × LCM

⇒ 161 × b = 23 × 1449

⇒ ∴ b = 23 ×1449/ 161 = 33327/161 = 207

Hence, the other number b is 207

Answer 2

Answer:

Given, HCF=23

LCM=1449

Let the two numbers be a and b. Let a=161. We have to find b.

We know that

HCF(a,b)×LCM(a,b)=a×b

⇒23×1449=161×b

⇒23× 1449 = b

161

⇒b=23×9

∴b=207

Thus, the other number is 207.

please mark me brainliest