Math, asked by anshumanmandarekar29, 5 days ago

The HCF of 2(x^2-y^2) and 5(x^3-y^3)​

Answers

Answered by AnanyaBaalveer
0

Answer:

2 {x}^{2}  -  2{y}^{2}

5 {x}^{3}  - 5 {y}^{3}

 {x}^{2}  -  {y}^{2}

hope helpful

Answered by asadbinabbas96
1

Step-by-step explanation:

2(x2 - y2) = 2(x - y)(x + y)

5(x3 - y3 ) = 5(x - y)( x2 + y2 + xy)

H.C.F. = (x - y)

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