Question

The HCF of 21 x^3 and y^7 and 35 x^5 and y^5​

Answer 1

Answer:

x

3

y

2

=x

3

×y

2

x

2

y

3

=x

2

×y

3

and x

4

y

4

=x

4

×y

4

∴ HCF =x

2

×y

2

=x

2

y

2

.