The HCF of 31, 43 and 47 is
Answers
Answer:
It is 1
Step-by-step explanation:
Because all the numbers are prime no.
Given:
Three numbers 31, 43, and 47,
To Find:
The HCF of the three numbers is?
Solution:
The given problem can be solved using prime factorization.
1. The HCF of three numbers is defined as the highest factor that is common between the three numbers such that it is perfectly divisible by all three numbers.
2. The given numbers are 31, 43, and 47. Factorize the numbers,
=> 31 = 1 x 31, ( 31 is a prime number ),
=> 43 = 1 x 43, ( 43 is a prime number ),
=> 47 = 1 x 47, ( 47 is a prime number ).
3. As all three numbers are prime numbers the only common factor between them is 1.
4. The HCF of the prime numbers is always 1 in all the cases. As the given numbers are also prime numbers, the HCF is 1.
Therefore, the HCF of 31, 43, and 47 is 1.