Math, asked by PulegariVaishnavi, 18 days ago

The HCF of 32,64,96,128​

Answers

Answered by tvaggala
0

Answer:

aggshakaoxkdnmwsjskskkskdocovkkdksls

Answered by sheeb12ansari
1

Answer:

The HCF of the given numbers is 32.

Step-by-step explanation:

Given: The numbers are 32,64,96,128​.

We have to find the HCF of the above numbers.

  • As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

The numbers are 32,64,96,128​.

First, we will find the factors of the above numbers.

The factors of 32 are: 1, 2, 4, 8, 16, 32

The factors of 64 are: 1, 2, 4, 8, 16, 32, 64

The factors of 96 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96

The factors of 128 are: 1, 2, 4, 8, 16, 32, 64, 128

From the above, we can see that 32 is the largest positive integer that divides each of the integers.

Then the greatest common factor(HCF) is 32.

In this problem, we are assuming we have to find the HCF of the given numbers.

Q. Find HCF of 32,64,96,128​.

Similar questions