the hcf of 33, 55 and 110 is
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1
119>55>33
by using Euclid's division lemma ,
55=33×1+22
33=22×1+11
22=11×2+0
so hcf of 55 and 33 is 11.
Now 110>11
Again by using Euclid's division lemma,
110=11×10+0
Hence hcf of 33,55 and 110 is 11.
If you face any difficulties ask me
by using Euclid's division lemma ,
55=33×1+22
33=22×1+11
22=11×2+0
so hcf of 55 and 33 is 11.
Now 110>11
Again by using Euclid's division lemma,
110=11×10+0
Hence hcf of 33,55 and 110 is 11.
If you face any difficulties ask me
Answered by
4
Find the prime factors of 33, 55 and 110:
33 = 3 x 11
55 = 5 x 11
110 = 2 x 5 x 11
Find the Highest Common Factor:
*For HCF, we picked up all the factors that are common across all the 3 numbers. The factor(s) MUST be common cross all the 3 numbers.
HCF = 11
Answer: The HCF of the 33, 55 and 110 is 11
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